Dimensions of `E/G` – Rankers Physics
Topic: Unit And Dimensions
Subtopic: Dimensions

Dimensions of `E/G`

If \(E\) and \(G\) respectively denote energy and gravitational constant, then \(\frac{E}{G}\) has the dimensions of:

[2021]

\([M][L]^{-1}[T]^{-1}\)
\([M^{2}][L]^{0}[T]^{0}\)
\([M^{2}][L]^{-2}[T]^{-1}\)
\([M^{2}][L]^{-1}[T]^{0}\)

Solution:

Energy \([E] = ML^2T^{-2}\) and Gravitational Constant \([G] = M^{-1}L^3T^{-2}\). So \([E/G] = M^2L^{-1}T^0\).

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