If \(E\) and \(G\) respectively denote energy and gravitational constant, then \(\frac{E}{G}\) has the dimensions of: [2021]\([M][L]^{-1}[T]^{-1}\)\([M^{2}][L]^{0}[T]^{0}\)\([M^{2}][L]^{-2}[T]^{-1}\)\([M^{2}][L]^{-1}[T]^{0}\)Solution:Energy \([E] = ML^2T^{-2}\) and Gravitational Constant \([G] = M^{-1}L^3T^{-2}\). So \([E/G] = M^2L^{-1}T^0\).
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