If \(x = at + bt^2\), where \(x\) is the distance travelled by the body in kilometres while \(t\) is the time in seconds, then the units of \(b\) is: [1989]\(km/s\)\(km s\)\(km/s^2\)\(km s^2\)Solution:By homogeneity, \([bt^2] = [x]\). So \([b] = [x]/[t^2] = km/s^2\).
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