Solution:
Statement (A) is correct as EMF is indeed a potential difference under open circuit. Statement (B) is incorrect because during charging, the terminal potential difference is \(V = E + Ir\), which is greater than the EMF \(E\).
Statement (A) is correct as EMF is indeed a potential difference under open circuit. Statement (B) is incorrect because during charging, the terminal potential difference is \(V = E + Ir\), which is greater than the EMF \(E\).
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