28. A straight line conductor of length $0.4 m$ is moved with a speed of $7 m/s$ perpendicular to a magnetic field of intensity $0.9 Wb/m^2$. The induced e.m.f. across the conductor is (1995)
Solution:
The motional e.m.f. induced across a straight conductor moving perpendicular to a magnetic field is $e = B v l$.
Given $B = 0.9 Wb/m^2$, $v = 7 m/s$, and $l = 0.4 m$.
$e = 0.9 \times 7 \times 0.4 = 2.52 V$.
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