10. A circular disc of radius $0.2 meter$ is placed in a uniform magnetic field of induction $\frac{1}{\pi} (\frac{wb}{m^2})$ in such a way that its axis makes an angle of $60^\circ$ with the magnetic field. The magnetic flux linked with the disc is: (2008)
Solution:
Magnetic flux is given by $\Phi = BA \cos\theta$.
Here, $\theta = 60^\circ$ (angle between the axis, which is the normal to the area, and the magnetic field).
$\Phi = \left(\frac{1}{\pi}\right) \cdot (\pi \cdot 0.2^2) \cdot \cos(60^\circ) = 0.04 \cdot 0.5 = 0.02 Wb$.
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