Solution:
Given $ T = 2\pi \sqrt{\frac{m}{k}} = 2\pi $ sec, we get $ m/k = 1 $. The original extension was $ x = \frac{mg}{k} $. Substituting $ m/k = 1 $ gives $ x = g $ metres. The spring decreases by this amount.
A body of mass 5 kg hangs from a spring and oscillates with a time period of $ 2\pi $ seconds. If the ball is removed, the length of the spring will decrease by: (1994)
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