Solution:
Time period $ T \propto l^{1/2} $. For small percentage changes, $ \frac{\Delta T}{T} \times 100 = \frac{1}{2} \left( \frac{\Delta l}{l} \times 100 \right) $. Thus, the time period increases by $ \frac{1}{2} \times 2\% = 1\% $.
Time period $ T \propto l^{1/2} $. For small percentage changes, $ \frac{\Delta T}{T} \times 100 = \frac{1}{2} \left( \frac{\Delta l}{l} \times 100 \right) $. Thus, the time period increases by $ \frac{1}{2} \times 2\% = 1\% $.
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