Rankers Physics
Topic: Oscillation

If the frequency of a spring is n after suspending mass M, now 4M mass is suspended from spring then the frequency will be: (1998)
2n
n/2
n
None of the above

Solution:

Frequency of a spring-mass system is $ f = \frac{1}{2\pi}\sqrt{\frac{k}{m}} \implies f \propto \frac{1}{\sqrt{m}} $. If mass is increased to 4M, the new frequency is $ f' = \frac{f}{\sqrt{4}} = \frac{n}{2} $.

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