NEET Physics Question

The particle executing simple harmonic motion has a kinetic energy $K_0 \cos^2 \omega t$. The maximum values of the potential energy and the total energy are respectively: (2007)

$K_0/2 \text{ and } K_0$

$K_0 \text{ and } 2K_0$

$K_0 \text{ and } K_0$

$0 \text{ and } 2K_0$

Solution:

The maximum kinetic energy is $K_0$.\nIn an ideal SHM without damping, the total energy remains conserved and equals the maximum kinetic energy, which is $K_0$.\nThe maximum potential energy is also equal to the total energy, which is $K_0$.

Rankers Physics

Solution:

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