Rankers Physics
Topic: Oscillation

If time of mean position from amplitude (extreme) position is $6\text{s}$. Then the frequency of S.H.M. will be: (1998)
$0.01 \text{ Hz}$
$0.02 \text{ Hz}$
$0.03 \text{ Hz}$
$0.04 \text{ Hz}$

Solution:

The time taken to travel from the extreme position to the mean position is $T/4$.\nThus, $T/4 = 6 \implies T = 24 \text{ s}$.\nFrequency $f = 1/T = 1/24 \approx 0.04 \text{ Hz}$.

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