Solution:
Equation is $x = a\sin^2\omega t = \frac{a}{2}(1 - \cos 2\omega t)$. This represents SHM about the mean position $x = a/2$. The angular frequency is $2\omega$. The frequency is $f = \frac{2\omega}{2\pi} = \frac{\omega}{\pi}$.
The displacement of a particle along the x-axis is given by $x = a\sin^2\omega t$. The motion of the particle corresponds to: (2010 Pre)
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