Rankers Physics
Topic: Thermal Physics

A black body has wavelength $\lambda_m$ corresponding to maximum energy at $2000 \text{ K}$. Its wavelength corresponding to maximum energy at $3000 \text{ K}$ will be: (2001)
$\frac{3}{2}\lambda_m$
$\frac{2}{3}\lambda_m$
$\frac{16}{81}\lambda_m$
$\frac{81}{16}\lambda_m$

Solution:

According to Wien's displacement law, $\lambda_{m1} T_1 = \lambda_{m2} T_2$. $\lambda_m (2000) = \lambda_{m2} (3000) \Rightarrow \lambda_{m2} = \frac{2000}{3000} \lambda_m = \frac{2}{3} \lambda_m$.

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