Solution:
Rate of heat flow $frac{dQ}{dt} = frac{K A Delta T}{L}$
Since $Delta T$ is same ($10^circ text{C}$) in both cases, the rate of heat flow will remain same i.e., $4.0 text{ J/s}$.
The two ends of a metal rod are maintained at temperatures $100^circ text{C}$ and $110^circ text{C}$. The rate of heat flow in the rod is found to be $4.0 text{ J/s}$. If the ends are maintained at temperatures $200^circ text{C}$ and $210^circ text{C}$, the rate of heat flow will be:
(2015)
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