Solution:
Heat required $Q = mc\Delta T = (\frac{4}{3}\pi r^3 \rho)c\Delta T$. For the same material and $\Delta T$, $Q \propto r^3$. Ratio $= (\frac{r_1}{r_2})^3 = (1.5)^3 = (\frac{3}{2})^3 = \frac{27}{8}$.
Heat required $Q = mc\Delta T = (\frac{4}{3}\pi r^3 \rho)c\Delta T$. For the same material and $\Delta T$, $Q \propto r^3$. Ratio $= (\frac{r_1}{r_2})^3 = (1.5)^3 = (\frac{3}{2})^3 = \frac{27}{8}$.
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