Question 1:
easyThe efficiency of heat engine working between \(27^\circ\text{C}\) and \(327^\circ\text{C}\) may be
The maximum possible efficiency (Carnot efficiency) is \(eta_{\text{max}} = 1 - \frac{T_L}{T_H} = 1 - \frac{300}{600} = 50\%\). Practical heat engines have efficiency less than or equal to 50%, so 50%, 35%, and 25% are all possible values.
Question 2:
moderateA carnot engine having an efficiency of $1/10$ as heat engine, is used as a refrigerator. If the work done on the system is $10\text{ J}$, the amount of energy absorbed from the reservoir at lower temperature is:
(2017-Delhi)
Coefficient of performance $\beta = \frac{1-eta}{\eta} = 9$. Heat absorbed from lower reservoir $Q_2 = \beta \times W = 9 \times 10\text{ J} = 90\text{ J}$.