Reason (R): Absolute zero kelvin is less than \(0^{\circ}C\) in Celsius scale.
Solution:
Assertion (A) is true. Extrapolation of the P-T (isochoric) graphs for ideal gases shows they converge to zero pressure at \(0 K\). Reason (R) is true; \(0 K\) is equal to \(-273.15^{\circ}C\), which is indeed less than \(0^{\circ}C\). However, R is a statement about temperature scale conversion and does not explain the behavior of the P-T graph.
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