Reason (R): Work done in a thermodynamical process is path independent.
Solution:
If \(P propto V\) (i.e., \(P=kV\)), then for an ideal gas \(PV=nRT\) implies \(kV^2=nRT\), so \(T \propto V^2\). Thus, temperature is not constant. (A) is false. Work done \(W = \int PdV\) depends on the path taken on a \(P-V\) diagram, so it is path dependent. (R) is false. Both (A) and (R) are false.
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