Solution:
Using the formula for thermal expansion, \( \frac{\Delta L}{L} \times 100 = \alpha \Delta T \times 100 \). Plugging in the values: \( 2 \times 10^{-5} \times 100 \times 100 = 0.2% \).
The percentage change in length of \( 1\text{ m} \) iron rod if its temperature changes by \( 100^circ\text{C} \) is (\( \alpha \) for iron is \( 2 \times 10^{-5}/^circ\text{C} \))
Leave a Reply