Solution:
The mean free path is given by $\lambda = \frac{1}{\sqrt{2}\pi n d^2}$. Since molecular diameter $d = 2r$, we have $\lambda \propto \frac{1}{d^2} \propto \frac{1}{r^2}$. Therefore, it is inversely proportional to $r^2$.
The mean free path is given by $\lambda = \frac{1}{\sqrt{2}\pi n d^2}$. Since molecular diameter $d = 2r$, we have $\lambda \propto \frac{1}{d^2} \propto \frac{1}{r^2}$. Therefore, it is inversely proportional to $r^2$.
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