Solution:
Given $C_p = \frac{7}{2}R$. Using $C_p - C_v = R$, we find $C_v = \frac{7}{2}R - R = \frac{5}{2}R$. The ratio of specific heats is $\gamma = \frac{C_p}{C_v} = \frac{7/2 R}{5/2 R} = \frac{7}{5}$.
The molar specific heat at constant pressure of an ideal gas is $\frac{7}{2}R$. The ratio of specific heat at constant pressure to that at constant volume is: (2006)
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