Rankers Physics
Topic: Thermal Physics
Subtopic: Kinetic Theory of Gases

The value of critical temperature in terms of Van der Waals' constant $a$ and $b$ is given by: (1996)
$T_c = \frac{8a}{27Rb}$
$T_c = \frac{27a}{8Rb}$
$T_c = \frac{a}{2Rb}$
$T_c = \frac{a}{27Rb}$

Solution:

The critical temperature $T_c$ for a real gas obeying the Van der Waals equation is theoretically derived as $T_c = \frac{8a}{27Rb}$, where $a$ and $b$ are the Van der Waals constants.

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