Solution:
The number of moles $n = \frac{\text{given mass}}{\text{molar mass}}$. For $5 \text{ g}$ of $O_2$ gas, $n = \frac{5}{32}$. Substituting this into the ideal gas equation $PV = nRT$, we get $PV = (\frac{5}{32})RT$.
The equation of state for $5 \text{ g}$ of oxygen at a pressure $P$ and temperature $T$, when occupying a volume $V$, will be: (2004)
Leave a Reply