Solution:
Heat required is given by \(Q = W \cdot c \cdot \Delta T\), where \(W\) is the water equivalent. Here, \(Q = 100\text{ g} \times 1\text{ cal/(g }^\circ\text{C)} \times 1^\circ\text{C} = 100\text{ cal}\) of energy.
Water equivalent of a metallic bar is \(100\text{ g}\), the energy required to increase its temperature by \(1^\circ\text{C}\) is
Leave a Reply