Solution:
According to Torricelli's Law, the velocity of efflux from a hole at a depth h is given by $$v = \sqrt{2gh}$$.
Since the volume flow rate per second
\( Q = \text{Area}\times\text{Velocity} \) is the same for both holes:
$$A_{\text{square}} \cdot v_1 = A_{\text{circle}} \cdot v_2$$
$$L^2 \sqrt{2gy} = (\pi R^2) \sqrt{2g(4y)}$$
$$L^2 = \pi R^2 \cdot 2$$
$$R = \frac{L}{\sqrt{2\pi}}$$
Thus, the correct option is Option 1.
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