Solution:
Volume conservation gives \(R = 10r\). Since surface energy \(E = T \cdot 4\pi R^2\), the ratio of surface energy of one small drop to one large drop is \(r^2 : R^2 = r^2 : 100r^2 = 1 : 100\).
What is ratio of surface energy of 1 small drop and 1 large drop, if 1000 small drops combined to form 1 large drop :
Leave a Reply