**List-I** (A) Soap solution is added to water (B) Arrangement taken in a freely falling lift (C) In a lift accelerating uniformly upward (D) Arrangement is taken in a lift accelerating uniformly downward
**List-II** (p) \(h\) decreases (q) \(h\) increases (r) \(h\) remains same (s) water will rise upto complete height of capillary (t) water level in capillary goes below the outside level
Solution:
Soap reduces surface tension, so \(h\) decreases (A-p). In a free fall, effective gravity \(g_{eff} = 0\), so water rises to full height (B-s). Upward acceleration increases \(g_{eff}\) hence \(h\) decreases (C-p). Downward acceleration decreases \(g_{eff}\) hence \(h\) increases (D-q).
Leave a Reply