Terminal Velocity of Coalescing Drops – Rankers Physics
Topic: Solid and Fluids
Subtopic: Fluid Dynamics

Terminal Velocity of Coalescing Drops

A drop of water falls in air with terminal velocity \(v_0\). If 27 such drops combine to form a big drop. Then terminal velocity of this new big drop will be:
\(3v_0\)
\(9v_0\)
\(27v_0\)
\(81v_0\)

Solution:

When 27 identical small drops of radius \(r\) coalesce, the radius \(R\) of the single large drop is \(R = 27^{1/3}r = 3r\). Since terminal velocity \(v \propto r^2\), the new terminal velocity is \(v' = 3^2 v_0 = 9v_0\).

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