NEET Physics Question - Semiconductor Physics - P-N Junction Diode and its applications

Assertion (A): The semiconductor used for fabrication of visible LED must at least have a band gap of 1.8 eV.

Reason (R): The spectral range of visible light is from 0.4 eV to 1.8 eV.

Both (A) & (R) are true and the (R) is the correct explanation of the (A)

Both (A) & (R) are true but the (R) is not the correct explanation of the (A)

(A) is true but (R) is false

Both (A) and (R) are false

Solution:

For visible light emission, the photon energy must be within the visible spectrum, which corresponds to energies from approximately \(1.8\) to \(3.1 \text{ eV}\). Thus, Assertion (A) is true. Reason (R) states the range from \(0.4\) to \(1.8 \text{ eV}\), which is incorrect for visible light.

Rankers Physics

LED Band Gap for Visible Light

Solution:

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