Solution:
The angular acceleration is \(\alpha = \frac{\tau}{I} = \frac{100}{300} = \frac{1}{3}\text{ rad/s}^2\). The final angular velocity starting from rest is \(\omega = \alpha t = \frac{1}{3} \times 3 = 1\text{ rad/s}\).
A constant torque of 100 N m turns a wheel of moment of inertia \(300\text{ kg m}^2\) about an axis passing through its centre. Starting from rest, its angular velocity after 3 s is
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