Angular Momentum from Kinetic Energy – Rankers Physics

Angular Momentum from Kinetic Energy

A particle of mass \(m\) is moving on a circle of radius \(R\) with kinetic energy \(K\). Then angular momentum of particle about centre of circle will be:

\(\sqrt{\frac{2K}{m}} R\)
\(\sqrt{mK} R\)
\(\sqrt{2mK} R\)
\(\sqrt{\frac{2m}{K}} R\)

Solution:

Kinetic energy \(K = \frac{p^2}{2m}\) gives momentum \(p = \sqrt{2mK}\) . Angular momentum is given by \(L = pR = \sqrt{2mK} R\).

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