NEET Refraction by Spherical Surfaces MCQs & PYQs

Oil immersion is used in microscopes to increase the numerical aperture (NA) and thus improve resolution. Thus, (A) is true.
The refractive index of the immersion oil is chosen to be very close to that of the objective lens glass, which minimizes refraction and maximizes the angle of light collected, increasing NA. Thus, (R) is true and is the correct explanation of (A).

Rainbows are formed due to dispersion and total internal reflection of sunlight by water droplets. Thus, (A) is true.
Rayleigh scattering states that the intensity of scattered light is inversely proportional to the fourth power of its wavelength \((I \propto 1/\lambda^4)), meaning shorter wavelengths (blue, violet) are scattered more than longer wavelengths (red). Thus, (R) is true.
However, (R) explains scattering, which is distinct from dispersion (dependence of refractive index on wavelength) responsible for the separation of colors in a rainbow. So, (R) does not explain (A).

Assertion (A) is true; the brain's retention of images for about \(1/16\) second creates motion from rapid stills. Reason (R) is true; the eye's lens system forms a real, inverted image on the retina. R describes a fundamental eye function, which is a prerequisite for A but not its direct explanation. Thus, both are true, but R does not explain A.

Chromatic aberration occurs because the refractive index of a lens material varies with wavelength (dispersion). A single lens always causes dispersion, leading to different focal points for different colors. Thus, both (A) and (R) are true, and (R) explains (A).

A real image is formed by the actual intersection of light rays and exists in space independently of a screen. It can be viewed by the eye even without a screen. Real images are formed in the medium where rays converge, typically air. Therefore, both assertion and reason are false.

For a rainbow, the sun must be behind the observer, and the rain in front. This means the observer's back should be towards the sun, not the raining side. Rainbow formation involves dispersion, total internal reflection, and refraction, not just direct reflection.

According to Cartesian sign convention, the focal length of a convex mirror is always positive as its principal focus is virtual and lies behind the mirror. Thus, (A) is false. While sign conventions involve directions, stating that distances measured in the direction of incident rays 'may be taken as negative' is generally incorrect or misleading; typically, these are taken as positive. Hence, (R) is also false. Thus, both (A) and (R) are false.

A simple microscope forms an erect, virtual, and enlarged image (A-H). A compound microscope forms a magnified, inverted, and virtual final image (B-E). An astronomical telescope has a virtual, inverted, high resolution final image (C-G). A terrestrial telescope has a virtual, erect, high resolution final image (D-F).

Focal length of a lens is independent of its aperture, so it remains $f$ . Intensity is proportional to the exposed area. Original area $A = \frac{\pi d^2}{4}$ . Covered area $a = \frac{\pi (d/2)^2}{4} = \frac{A}{4}$ . Remaining area $A' = A - \frac{A}{4} = \frac{3A}{4}$ . New intensity is proportional to remaining area, so $I' = \frac{3I}{4}$ .

Negative magnification implies a real inverted image, which is only formed by a concave mirror. So A ( $m = -2$ ) and B ( $m = -1/2$ ) match with (2) Concave and (3) Real. Positive magnification > 1 ( $m = +2$ ) implies a virtual magnified image, formed only by a concave mirror (2, 4). Positive magnification < 1 implies a virtual diminished image, formed by a convex mirror (1, 4).