Solution:
Using the prism formula: \(\mu = \frac{\sin\left(\frac{A + D_m}{2}\right)}{\sin(A/2)}\). Since \(A = D_m = 60^\circ\), \(\mu = \frac{\sin(60^\circ)}{\sin(30^\circ)} = \sqrt{3} \approx 1.732\).
Using the prism formula: \(\mu = \frac{\sin\left(\frac{A + D_m}{2}\right)}{\sin(A/2)}\). Since \(A = D_m = 60^\circ\), \(\mu = \frac{\sin(60^\circ)}{\sin(30^\circ)} = \sqrt{3} \approx 1.732\).
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