Assertion (A): In a SHM, kinetic and potential energies become equal when the displacement is \(\frac{1}{\sqrt{2}}\) times the amplitude.
Reason (R): In SHM, kinetic energy is zero when potential energy is maximum.
Solution:
Equating \(KE = \frac{1}{2}k(A^2 - x^2)\) and \(PE = \frac{1}{2}kx^2\) gives \(x = \frac{A}{\sqrt{2}}\). Maximum PE occurs at extremes where KE is zero. Both statements are true, but (R) does not explain (A).
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