Rankers Physics
Topic: Modern Physics
Subtopic: Nucleus

200 MeV of energy can be obtained by per fission. In a reactor generating 1000 kW find the number of nuclei under going the fission per second :
1000
\[2\times 10^{8}\]
\[3.125\times 10^{16}\]
931

No solution provided for this question.

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