In the given nuclear reaction A, B, C, D, E represents A = 234, B = 90, C = 234, D = 91, E = βA = 234, B = 90, C = 238, D = 94, E = αA = 238, B = 93, C = 234, D = 91, E = βA = 234, B = 90, C = 234, D = 93, E = αNo solution provided for this question.
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