Energy in orbit of helium ion – Rankers Physics
Topic: Modern Physics
Subtopic: Atomic Structure

Energy in orbit of helium ion

If the energy of a hydrogen atom in \(n^{text{th}}\) orbit is \(E\), then energy in the \(n^{text{th}}\) orbit of a singly ionized helium atom will be
\(\frac{E}{4}\)
\(4E\)
\(2E\)
\(\frac{E}{2}\)

Solution:

The energy in the \(n^{text{th}}\) orbit is proportional to \(Z^2\), where \(Z\) is the atomic number. For hydrogen, \(Z=1\) and for helium, \(Z=2\). Therefore, the energy of singly ionized helium is \(2^2 = 4\) times the energy of hydrogen, which is \(4E\).

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