Maximum Kinetic Energy of Photoelectrons

The stopping potential in the photoelectric experiment is 1.6 V. The maximum kinetic energy of photoelectrons emitted is

\[2.4 × 10^{–19} J\]

\[2.56 × 10^{–19} J\]

\[1.86 × 10^{–19} J\]

\[1.4 × 10^{–19} J\]

Maximum kinetic energy of photoelectrons is \(K_{\text{max}} = e V_s = 1.6 \times 1.6 \times 10^{-19}\text{ J} = 2.56 \times 10^{-19}\text{ J}\).