Solution:
The radius of a nucleus is given by \(R \propto A^{1/3}\). Therefore, \(frac{R'}{R} = \left(\frac{16}{2}\right)^{1/3} = 8^{1/3} = 2\), so \(R' = 2R\).
The radius of a nucleus is given by \(R \propto A^{1/3}\). Therefore, \(frac{R'}{R} = \left(\frac{16}{2}\right)^{1/3} = 8^{1/3} = 2\), so \(R' = 2R\).
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