Topic: Magnetic Effects of Current
Subtopic: Magnetic Field Due to Straight Current Carrying Wire
A semi-infinite straight conductor carries a current I P is a point at perpendicular distance a
from the conductor as shown. The field at P due to the conductor is :

\[B=\frac{\mu_{0}I}{4\pi a}(1+sin\phi):outwards\]
\[B=\frac{\mu_{0}I}{4\pi a}(1+cos\phi):outwards\]
\[B=\frac{\mu_{0}I}{4\pi a}(1+sin\phi):inwards\]
\[B=\frac{\mu_{0}I}{4\pi a}(1+cos\phi):inwards\]
No solution provided for this question.
Leave a Reply