Magnetic Induction of Long Straight Wire – Rankers Physics
Topic: Magnetic Effects of Current
Subtopic: Force Acting on Current Carrying Conductor

Magnetic Induction of Long Straight Wire

A long straight wire carries an electric current \(4\text{ A}\). The magnetic induction at a perpendicular distance \(2\text{ m}\) from the wire is
\(2 \times 10^{-7}\text{ T}\)
\(4 \times 10^{-7}\text{ T}\)
\(2 \times 10^{-8}\text{ T}\)
\(4 \times 10^{-8}\text{ T}\)

Solution:

The magnetic field near a long straight wire is given by \(B = \frac{\mu_0 I}{2\pi r}\). Substituting \(I = 4\text{ A}\) and \(r = 2\text{ m}\) with \(\mu_0 = 4\pi \times 10^{-7}\text{ T m/A}\) gives \(B = \frac{4\pi \times 10^{-7} \times 4}{4\pi} = 4 \times 10^{-7}\text{ T}\).

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