Condition for Unaccelerated Motion in E & B Fields – Rankers Physics
Topic: Magnetic Effects of Current
Subtopic: Force Acting on Moving Charges

Condition for Unaccelerated Motion in E & B Fields

If a charged particle goes unaccelerated in a region containing electric & magnetic fields: (a) \(\vec{E}\) must be perpendicular to \(\vec{B}\) (b) \(\vec{v}\) must be perpendicular to \(\vec{E}\) (c) \(\vec{v}\) must be perpendicular to \(\vec{B}\) (d) \(E\) must be equal to \(vB\)
(a), (b)
(c), (d)
(a), (c)
(b), (d)

Solution:

For the net force to be zero, \(\vec{F}_e + \vec{F}_b = 0 ⇒ \vec{E} = -(\vec{v} \times \vec{B})\). Since \(\vec{E}\) is the cross product, it must be perpendicular to both \(\vec{B}\) and \(\vec{v}\).

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