Solution:
Stopping distance \(s\) is proportional to \(u^2\). When the speed is doubled (from 50 to 100), the stopping distance increases by a factor of 4. Thus, \(s' = 4 \times 6 = 24\text{ m}\).
A car moving with a speed of \(50\text{ kmh}^{-1}\), can be stopped by brakes after at least \(6\text{ m}\). If the same car is moving at a speed of \(100\text{ kmh}^{-1}\), the minimum stopping distance is
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