Solution:
Velocity \(v = 3t^2 - 12t + 3\) and acceleration \(a = 6t - 12\). Acceleration is zero at t = 2 s. Substituting \(t = 2\) in velocity equation gives \(v = 3(4) - 24 + 3 = -9 \text{ ms}^{-1}\).
A particle moves along a straight line such that its displacement at any time t is given by \(s = t^3 - 6t^2 + 3t + 4\). The velocity when its acceleration is zero is
Leave a Reply