A car is moving with velocity of \( 20\text{ m/s} \) on a straight road. A scooterist wishes to overtake the car in \( 60\text{ s} \). If the car is at a distance of \( 1.5\text{ km} \) ahead, then the velocity with which the scooterist has to chase the car is
Solution:
Relative velocity required: \( v_{\text{rel}} = \frac{\text{distance}}{\text{time}} = \frac{1500\text{ m}}{60\text{ s}} = 25\text{ m/s} \). Since \( v_{\text{rel}} = v_s - v_c \), we get \( v_s = v_c + v_{\text{rel}} = 20 + 25 = 45\text{ m/s} \).
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