Solution:
The distance travelled in the \( n^{\text{th}} \) second is \( s_n = u + \frac{a}{2}(2n - 1) \). Substituting \( u = 0 \), \( a = 2 \, \text{m/s}^2 \), and \( n = 4 \) yields \( s_4 = 0 + \frac{2}{2}(2(4) - 1) = 7 \, \text{m} \).
A car starts from rest, accelerates uniformly at \( 2 \, \text{m/s}^2 \). The distance travelled by the car in fourth second is
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