Projectile Motion – Horizontal Range – Rankers Physics
Topic: Kinematics
Subtopic: Ground to Ground Projectile

Projectile Motion – Horizontal Range

Assertion (A): In projectile motion (from ground to ground projection), horizontal range is always same for angle of projection \(\theta\) and \(90^\circ - \theta\).
Reason (R): Horizontal range is independent of angle of projection.
 
(1) Both (A) & (R) are true and the (R) is the correct explanation of the (A)
(2) Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(3) (A) is true but (R) is false
(4) Both (A) and (R) are false

Solution:

Assertion (A): The range formula is \(R = \frac{u^2 sin(2\theta)}{g}\). For angle \((90^\circ - \theta)\), \(R' = \frac{u^2 sin(2(90^\circ - \theta))}{g} = \frac{u^2 sin(180^\circ - 2\theta)}{g} = \frac{u^2 sin(2\theta)}{g} = R\). So (A) is True.
Reason (R): The horizontal range clearly depends on the angle of projection (theta) via (sin(2theta)). So (R) is False.
Since (A) is true and (R) is false, option (3) is correct.

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