Assertion (A): A body dropped from a height of \(10 \text{ m}\) from the ground will have the velocity \(5 \text{ m/s}\) at the height of \(5 \text{ m}\).
Reason (R): At the height of \(5 \text{ m}\) from the ground, the acceleration due to gravity is \(5 \text{ m/s}^2\).
Solution:
Formula: \(v^2 = u^2 + 2gs\), \(g \approx 9.8 \text{ m/s}^2\).
Solution: (A) is false; for a fall of \(5 \text{ m}\) from rest, \(v = \sqrt{2gh} = \sqrt{2 \times 9.8 \times 5} = \sqrt{98} \approx 9.9 \text{ m/s}\), not \(5 \text{ m/s}\). (R) is false; acceleration due to gravity is approximately \(9.8 \text{ m/s}^2\) or \(10 \text{ m/s}^2\), not \(5 \text{ m/s}^2\).
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