Displacement from Velocity-Time Graph – Rankers Physics
Topic: Kinematics
Subtopic: 1. Distance and Displacement

Displacement from Velocity-Time Graph


Assertion (A): Displacement of a body is vector sum of the area under velocity-time graph.
Reason (R): Displacement is a vector quantity.
 
(1) Both (A) & (R) are true and the (R) is the correct explanation of the (A)
(2) Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(3) (A) is true but (R) is false
(4) Both (A) and (R) are false

Solution:

The area under a velocity-time graph indeed represents displacement, considering areas above the time axis as positive and below as negative, which is a vector sum.


Displacement is a vector quantity, meaning it has both magnitude and direction. This vector nature directly explains why the signed area (vector sum) under the velocity-time graph yields displacement.


Both (A) and (R) are true, and (R) correctly explains (A).

Leave a Reply

Your email address will not be published. Required fields are marked *