Solution:
Both maximum height \(H = \frac{u^2 \sin^2\theta}{2g}\) and time of flight \(T = \frac{2u \sin\theta}{g}\) are proportional to velocity \(u\). Since particle B has a larger velocity, both values are greater for B.
Two particles A and B are projected from ground at an angle of 30° with the horizontal with velocity 20 m/s and 40 m/s respectively. The maximum height and time of flight are both greater for which particle?
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