Solution:
Since acceleration is uniform, the distance is given by the formula \(s = \frac{u+v}{2} \times t\). Substituting \(u=20\text{ m/s}\), \(v=60\text{ m/s}\), and \(t=5\text{ s}\), we get \(s = \frac{20+60}{2} \times 5 = 200\text{ m}\).
If velocity of a car increases uniformly from \(20\text{ m/sec}\) to \(60\text{ m/sec}\) in a time interval of 5 seconds. Then distance travelled during this interval is:
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